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7
duty cycle of the sync pulses can vary from 10% to 90%. The
frequency foldback feature is disabled during the sync
mode.
Figure 4. A NCV51411 Buck Regulator is Synchronized
to an External 350 kHz Pulse Signal
Power Switch and Current Limit
The collector of the builtin NPN power switch is
connected to the V
IN
pin, and the emitter to the V
SW
pin.
When the switch turns on, the V
SW
voltage is equal to the
V
IN
minus switch Saturation Voltage. In the buck regulator,
the V
SW
voltage swings to one diode drop below ground
when the power switch turns off, and the inductor current is
commutated to the catch diode. Due to the presence of high
pulsed current, the traces connecting the V
SW
pin, inductor
and diode should be kept as short as possible to minimize the
noise and radiation. For the same reason, the input capacitor
should be placed close to the V
IN
pin and the anode of the
diode.
The saturation voltage of the power switch is dependent
on the switching current, as shown in Figure 5.
Figure 5. The Saturation Voltage of the Power Switch
Increases with the Conducting Current
0 0.5 1.0 1.5
SWITCHING CURRENT (A)
V
IN
V
SW
(V)
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
The NCV51411 contains pulsebypulse current limiting
to protect the power switch and external components. When
the peak of the switching current reaches the Current Limit,
the power switch turns off after the Current Limit Delay. The
switch will not turn on until the next switching cycle. The
current limit threshold is independent of switching duty
cycle. The maximum load current, given by the following
formula under continuous conduction mode, is less than the
Current Limit due to the ripple current.
I
O(MAX)
+ I
LIM
*
V
O
(V
IN
* V
O
)
2(L)(V
IN
)(f
s
)
where:
f
S
= switching frequency,
I
LIM
= current limit threshold,
V
O
= output voltage,
V
IN
= input voltage,
L = inductor value.
When the regulator runs under current limit, the
subharmonic oscillation may cause low frequency
oscillation, as shown in Figure 6. Similar to current mode
control, this oscillation occurs at the duty cycle greater than
50% and can be alleviated by using a larger inductor value.
The current limit threshold is reduced to Foldback Current
when the FB pin falls below Foldback Threshold. This
feature protects the IC and external components under the
power up or overload conditions.
Figure 6. The Regulator in Current Limit
NCV51411
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8
BOOST Pin
The BOOST pin provides base driving current for the
power switch. A voltage higher than V
IN
provides required
headroom to turn on the power switch. This in turn reduces
IC power dissipation and improves overall system
efficiency. The BOOST pin can be connected to an external
booststrapping circuit which typically uses a 0.1 mF capacitor
and a 1N914 or 1N4148 diode, as shown in Figure 1. When the
power switch is turned on, the voltage on the BOOST pin is
equal to
V
BOOST
+ V
IN
) V
O
* V
F
where:
V
F
= diode forward voltage.
The anode of the diode can be connected to any DC
voltage as well as the regulated output voltage (Figure 1).
However, the maximum voltage on the BOOST pin shall not
exceed 40 V.
As shown in Figure 7, the BOOST pin current includes a
constant 7.0 mA predriver current and base current
proportional to switch conducting current. A detailed
discussion of this current is conducted in Thermal
Consideration section. A 0.1 mF capacitor is usually
adequate for maintaining the Boost pin voltage during the on
time.
Figure 7. The Boost Pin Current Includes 7.0 mA
PreDriver Current and Base Current when the
Switch is Turned On. The Beta Decline of the
Power Switch Further Increases the Base
Current at High Switching Current
0 0.5 1.0 1.5
SWITCHING CURRENT (A)
BOOST PIN CURRENT (mA)
0
5
10
15
20
25
30
Shutdown
The internal power switch will not turn on until the V
IN
pin rises above the Startup Voltage. This ensures no
switching until adequate supply voltage is provided to the
IC. The IC transitions to sleep mode when the SHDNB pin
is pulled low. In sleep mode, the internal power switch
transistor remains off and supply current is reduced to the
Shutdown Quiescent Current value (20 mA typical). This pin
has an internal pull-up current source, so defaults to high
(enabled) state when not connected.
Figure 8. SHDNB pin equivalent internal circuit (a)
and practical interface examples (b), (c).
0.65V
20k
8V
SHDNB
To internal
bias rails
SHDNB
2V to 5V
SHDNB
(a)
(b)
(c)
Z1
Q1
Q2
D1
V
IN
80k
I1
5mA
Figure 8(a) depicts the SHDNB pin equivalent internal
circuit. If the pin is open, current source I1 flows into the
base of Q1, turning both Q1 and Q2 on. In turn, Q2 collector
current enables the various internal power rails. In
Figure 8(b), a standard logic gate is used to pull the pin low
by shunting I1 to ground, which places the IC in sleep
(shutdown) mode. Note that, when the gate output is logical
high, the voltage at the SHDNB pin will rise to the internal
clamp voltage of 8 V. This level exceeds the maximum
output rating for most common logic families. Protection
Zener diode Z1 permits the pin voltage to rise high enough
to enable the IC, but remain less than the gate output voltage
rating. In Figure 8(c), a single open-collector general-
purpose NPN transistor is used to pull the pin low. Since
transistors generally have a maximum collector voltage
rating in excess of 8 V, the protection Zener diode in
Figure 8(b) is not required.
Startup
During power up, the regulator tends to quickly charge up
the output capacitors to reach voltage regulation. This gives
rise to an excessive inrush current which can be detrimental
to the inductor, IC and catch diode. In V
2
control , the
compensation capacitor provides SoftStart with no need
for extra pin or circuitry. During the power up, the Output
Source Current of the error amplifier charges the
compensation capacitor which forces V
C
pin and thus output
voltage ramp up gradually. The SoftStart duration can be
calculated by
T
SS
+
V
C
C
COMP
I
SOURCE
where:
V
C
= V
C
pin steadystate voltage, which is approximately
equal to error amplifiers reference voltage.
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9
C
COMP
= Compensation capacitor connected to the V
C
pin
I
SOURCE
= Output Source Current of the error amplifier.
Using a 0.1 mF C
COMP
, the calculation shows a T
SS
over
5.0 ms which is adequate to avoid any current stresses.
Figure 9 shows the gradual rise of the V
C
, V
O
and envelope
of the V
SW
during power up. There is no voltage overshoot
after the output voltage reaches the regulation. If the supply
voltage rises slower than the V
C
pin, output voltage may
overshoot.
Figure 9. The Power Up Transition of NCV51411
Regulator
Short Circuit
When the V
FB
pin voltage drops below Foldback
Threshold, the regulator reduces the peak current limit by
40% and switching frequency to 1/4 of the nominal
frequency. These features are designed to protect the IC and
external components during over load or short circuit
conditions. In those conditions, peak switching current is
clamped to the current limit threshold. The reduced
switching frequency significantly increases the ripple
current, and thus lowers the DC current. The short circuit can
cause the minimum duty cycle to be limited by Minimum
Output Pulse Width. The foldback frequency reduces the
minimum duty cycle by extending the switching cycle. This
protects the IC from overheating, and also limits the power
that can be transferred to the output. The current limit
foldback effectively reduces the current stress on the
inductor and diode. When the output is shorted, the DC
current of the inductor and diode can approach the current
limit threshold. Therefore, reducing the current limit by 40%
can result in an equal percentage drop of the inductor and
diode current. The short circuit waveforms are captured in
Figure 10, and the benefit of the foldback frequency and
current limit is selfevident.
Figure 10. In Short Circuit, the Foldback Current and
Foldback Frequency Limit the Switching Current to
Protect the IC, Inductor and Catch Diode
Thermal Considerations
A calculation of the power dissipation of the IC is always
necessary prior to the adoption of the regulator. The current
drawn by the IC includes quiescent current, predriver
current, and power switch base current. The quiescent
current drives the low power circuits in the IC, which
include comparators, error amplifier and other logic blocks.
Therefore, this current is independent of the switching
current and generates power equal to
W
Q
+ V
IN
I
Q
where:
I
Q
= quiescent current.
The predriver current is used to turn on/off the power
switch and is approximately equal to 12 mA in worst case.
During steady state operation, the IC draws this current from
the Boost pin when the power switch is on and then receives
it from the V
IN
pin when the switch is off. The predriver
current always returns to the V
SW
pin. Since the predriver
current goes out to the regulators output even when the
power switch is turned off, a minimum load is required to
prevent overvoltage in light load conditions. If the Boost pin
voltage is equal to V
IN
+ V
O
when the switch is on, the power
dissipation due to predriver current can be calculated by
W
DRV
+ 12 mA (V
IN
* V
O
)
V
O
2
V
IN
)
The base current of a bipolar transistor is equal to collector
current divided by beta of the device. Beta of 60 is used here
to estimate the base current. The Boost pin provides the base
current when the transistor needs to be on. The power
dissipated by the IC due to this current is

NCV51411DR2

Mfr. #:
Manufacturer:
ON Semiconductor
Description:
Switching Voltage Regulators 1.5A Low Voltage
Lifecycle:
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