16
LTC1625
where L1, L2, etc. are the individual losses as a percentage
of input power. It is often useful to analyze individual
losses to determine what is limiting the efficiency and
which change would produce the most improvement.
Although all dissipative elements in the circuit produce
losses, four main sources usually account for most of the
losses in LTC1625 circuits:
1. INTV
CC
current. This is the sum of the MOSFET driver
and control currents. The driver current results from
switching the gate capacitance of the power MOSFETs.
Each time a MOSFET gate is switched on and then off,
a packet of gate charge Q
g
moves from INTV
CC
to
ground. The resulting current out of INTV
CC
is typically
much larger than the control circuit current. In continu-
ous mode, I
GATECHG
= f(Q
g(TOP)
+ Q
g(BOT)
).
By powering EXTV
CC
from an output-derived source,
the additional V
IN
current resulting from the driver and
control currents will be scaled by a factor of Duty Cycle/
Efficiency. For example, in a 20V to 5V application at
400mA load, 10mA of INTV
CC
current results in ap-
proximately 3mA of V
IN
current. This reduces the loss
from 10% (if the driver was powered directly from V
IN
)
to about 3%.
2. DC I
2
R Losses. Since there is no separate sense resis-
tor, DC I
2
R losses arise only from the resistances of the
MOSFETs and inductor. In continuous mode the aver-
age output current flows through L, but is “chopped”
between the top MOSFET and the bottom MOSFET. If
the two MOSFETs have approximately the same R
DS(ON)
,
then the resistance of one MOSFET can simply be
summed with the resistance of L to obtain the DC I
2
R
loss. For example, if each R
DS(ON)
= 0.05 and R
L
=
0.15, then the total resistance is 0.2. This results in
losses ranging from 2% to 8% as the output current
increases from 0.5A to 2A for a 5V output. I
2
R losses
cause the efficiency to drop at high output currents.
3. Transition losses apply only to the topside MOSFET,
and only when operating at high input voltages (typi-
cally 20V or greater). Transition losses can be esti-
mated from:
Transition Loss = (1.7)(V
IN
2
)(I
O(MAX)
)(C
RSS
)(f)
APPLICATIONS INFORMATION
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4. LTC1625 V
IN
supply current. The V
IN
current is the DC
supply current to the controller excluding MOSFET gate
drive current. Total supply current is typically about
850µA. If EXTV
CC
is connected to 5V, the LTC1625 will
draw only 330µA from V
IN
and the remaining 520µA will
come from EXTV
CC
. V
IN
current results in a small
(<1%) loss which increases with V
IN
.
Other losses including C
IN
and C
OUT
ESR dissipative
losses, Schottky conduction losses during dead time
and inductor core losses, generally account for less
than 2% total additional loss.
Checking Transient Response
The regulator loop response can be checked by looking at
the load transient response. Switching regulators take
several cycles to respond to a step in DC (resistive) load
current. When a load step occurs, V
OUT
immediately shifts
by an amount equal to (I
LOAD
)(ESR), where ESR is the
effective series resistance of C
OUT
, and C
OUT
begins to
charge or discharge. The regulator loop acts on the
resulting feedback error signal to return V
OUT
to its steady-
state value. During this recovery time V
OUT
can be moni-
tored for overshoot or ringing which would indicate a
stability problem. The I
TH
pin external components shown
in Figure 1 will provide adequate compensation for most
applications.
A second, more severe transient is caused by connecting
loads with large (>1µF) supply bypass capacitors. The
discharged bypass capacitors are effectively put in parallel
with C
OUT
, causing a rapid drop in V
OUT
. No regulator can
deliver enough current to prevent this problem if the load
switch resistance is low and it is driven quickly. The only
solution is to limit the rise time of the switch drive in order
to limit the inrush current to the load.
Automotive Considerations: Plugging into the
Cigarette Lighter
As battery-powered devices go mobile, there is a natural
interest in plugging into the cigarette lighter in order to
conserve or even recharge battery packs during opera-
tion. But before you connect, be advised: you are plug-
ging into the supply from hell. The main battery line in an
17
LTC1625
APPLICATIONS INFORMATION
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automobile is the source of a number of nasty potential
transients, including load dump, reverse and double
battery.
Load dump is the result of a loose battery cable. When the
cable breaks connection, the field collapse in the alternator
can cause a positive spike as high as 60V which takes
several hundred milliseconds to decay. Reverse battery is
just what it says, while double battery is a consequence of
tow truck operators finding that a 24V jump start cranks
cold engines faster than 12V.
The network shown in Figure 8 is the most straightforward
approach to protect a DC/DC converter from the ravages
of an automotive battery line. The series diode prevents
current from flowing during reverse battery, while the
transient suppressor clamps the input voltage during load
dump. Note that the transient suppressor should not
conduct during double-battery operation, but must still
clamp the input voltage below breakdown of the converter.
Although the LTC1625 has a maximum input voltage of
36V, most applications will be limited to 30V by the
MOSFET V
(BR)DSS
.
For 40% ripple current at maximum V
IN
the inductor
should be:
L
V
kHz A
V
V
H
33
225 0 4 2
1
33
22
16
.
( )( . )( )
.
Choosing a standard value of 15µH results in a maximum
ripple current of:
I
V
kHz H
V
V
A
L MAX()
.
()()
.
.=
µ
=
33
225 15
1
33
22
083
Next, check that the minimum value of the current limit is
acceptable. Assume a junction temperature close to a
70°C ambient with ρ
80°C
= 1.3.
I
mV
AA
LIMIT
=
150
0 042 1 3
1
2
083 23
(. )(.)
–. .
This is comfortably above I
O(MAX)
= 2A. Now double-check
the assumed T
J
:
P
V
V
A
A pF kHz
mW mW mW
TOP
=Ω+
=+=
33
22
23 13 0042
1 7 22 2 3 180 225
43 77 120
2
2
.
(. )(.)(. )
(.)( )(. )( )( )
T
J
= 70°C + (120mW)(50°C/W) = 76°C
Since ρ(76°C) ρ(80°C), the solution is self-consistent.
A short circuit to ground will result in a folded back
current of:
I
mV V s
H
A
SC
=
+
µ
µ
=
30
003 11
1
2
15 0 5
15
12
(. )(.)
()(.)
.
with a typical value of R
DS(ON)
and ρ(50°C) = 1.1. The
resulting power dissipated in the bottom MOSFET is:
P
VV
V
AmW
BOT
=Ω=
15 3 3
15
12 11 003 37
2
–.
(. )(.)(. )
which is less than under full load conditions.
V
IN
TRANSIENT VOLTAGE
SUPPRESSOR
GENERAL INSTRUMENT
1.5KA24A
12V
LTC1625
50A I
PK
RATING
1625 F08
PGND
Figure 8. Automotive Application Protection
Design Example
As a design example, take a supply with the following
specifications: V
IN
= 12V to 22V (15V nominal), V
OUT
=
3.3V, I
O(MAX)
= 2A, and f = 225kHz. The required R
DS(ON)
can immediately be estimated:
R
mV
A
DS ON()
()(.)
.==
120
213
0 046
A 0.042 Siliconix Si4412DY MOSFET (θ
JA
= 50°C/W) is
close to this value.
18
LTC1625
APPLICATIONS INFORMATION
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+
C
SS
0.1µF
R
C
10k
C
C1
470pF
C
C2
220pF
M1
Si4412DY
C
IN
22µF
35V
×2
V
IN
12V TO 22V
V
OUT
3.3V
2A
M2
Si4412DY
D1
MBRS140T3
D
B
CMDSH-3
C
VCC
4.7µF
1625 F09
OPEN
INTV
CC
V
IN
TK
EXTV
CC
LTC1625
SYNC
V
PROG
SW
TG
BOOST
INTV
CC
BG
RUN/SS
FCB
I
TH
SGND
V
OSENSE
PGND
1
2
3
4
5
6
7
8
16
15
14
13
12
11
10
9
C
B
0.1µF
L1
15µH
+
C
OUT
100µF
10V
0.065
×2
+
C
IN
: AVX TPSE226M035R0300
C
OUT
: AVX TPSD107M010R0065
L1: SUMIDA CDRH125-150MC
Figure 9. 3.3V/2A Fixed Output at 225kHz
C
IN
is chosen for an RMS current rating of at least 1A at
temperature. C
OUT
is chosen with an ESR of 0.033 for
low output ripple. The output ripple in continuous mode
will be highest at the maximum input voltage and is
approximately:
V
O
= (I
L(MAX)
)(ESR) = (0.83A)(0.033) = 27mV
The complete circuit is shown in Figure 9.
PC Board Layout Checklist
When laying out the printed circuit board, the following
checklist should be used to ensure proper operation of the
LTC1625. These items are also illustrated graphically in
the layout diagram of Figure 10. Check the following in
your layout:
1) Connect the TK lead directly to the drain of the topside
MOSFET. Then connect the drain to the (+) plate of C
IN
.
This capacitor provides the AC current to the top
MOSFET.
2) The power ground pin connects directly to the source of
the bottom N-channel MOSFET. Then connect the source
to the anode of the Schottky diode and (–) plate of C
IN
,
which should have as short lead lengths as possible.
3) The LTC1625 signal ground pin must return to the (–)
plate of C
OUT
. Connect the (–) plate of C
OUT
to power
ground at the source of the bottom MOSFET
4) Keep the switch node SW away from sensitive small-
signal nodes. Ideally the switch node should be placed
on the opposite side of the power MOSFETs from the
LTC1625.
5) Connect the INTV
CC
decoupling capacitor C
VCC
closely
to the INTV
CC
pin and the power ground pin. This
capacitor carries the MOSFET gate drive current.
6) Does the V
OSENSE
pin connect directly to the (+) plate of
C
OUT
? In adjustable applications, the resistive divider
(R1, R2) must be connected between the (+) plate of
C
OUT
and signal ground. Place the divider near the
LTC1625 in order to keep the high impedance V
OSENSE
node short.
7) For applications with multiple switching power con-
verters connected to the same V
IN
, ensure that the input
filter capacitance for the LTC1625 is not shared with the
other converters. AC input current from another con-
verter will cause substantial input voltage ripple that
may interfere with proper operation of the LTC1625. A
few inches of PC trace or wire (100nH) between C
IN
and V
IN
is sufficient to prevent sharing.

LTC1625IS#PBF

Mfr. #:
Manufacturer:
Analog Devices / Linear Technology
Description:
Switching Voltage Regulators NoRsense Current Mode DC/DC
Lifecycle:
New from this manufacturer.
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