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10
Procedure (Fixed Output Voltage Version) In order to simplify the switching regulator design, a step−by−step design
procedure and example is provided.
Procedure Example
Given Parameters:
V
out
= Regulated Output Voltage (3.3 V, 5.0 V, 12 V or 15 V)
V
in(max)
= Maximum Input Voltage
I
Load(max)
= Maximum Load Current
Given Parameters:
V
out
= 5.0 V
V
in(max)
= 15 V
I
Load(max)
= 0.4 A
1. Controller IC Selection
According to the required input voltage, output voltage and
current, select the appropriate type of the controller IC output
voltage version.
1. Controller IC Selection
According to the required input voltage, output voltage,
current polarity and current value, use the LM2574−5
controller IC.
2. Input Capacitor Selection (C
in
)
To prevent large voltage transients from appearing at the input
and for stable operation of the converter, an aluminium or
tantalum electrolytic bypass capacitor is needed between the
input pin +V
in
and ground pin Gnd. This capacitor should be
located close to the IC using short leads. This capacitor should
have a low ESR (Equivalent Series Resistance) value.
2. Input Capacitor Selection (C
in
)
A 22 mF, 25 V aluminium electrolytic capacitor located near
to the input and ground pins provides sufficient bypassing.
3. Catch Diode Selection (D1)
A. Since the diode maximum peak current exceeds the
regulator maximum load current, the catch diode current
rating must be at least 1.2 times greater than the maximum
load current. For a robust design the diode should have a
current rating equal to the maximum current limit of the
LM2574 to be able to withstand a continuous output short.
B. The reverse voltage rating of the diode should be at least
1.25 times the maximum input voltage.
3. Catch Diode Selection (D1)
A. For this example the current rating of the diode is 1.0 A.
B. Use a 20 V 1N5817 Schottky diode, or any of the
suggested fast recovery diodes shown in Table 1.
4. Inductor Selection (L1)
A. According to the required working conditions, select the
correct inductor value using the selection guide from
Figures 19 to 23.
B. From the appropriate inductor selection guide, identify the
inductance region intersected by the Maximum Input Voltage
line and the Maximum Load Current line. Each region is
identified by an inductance value and an inductor code.
C. Select an appropriate inductor from the several different
manufacturers part numbers listed in Table 2. The designer
must realize that the inductor current rating must be higher
than the maximum peak current flowing through the inductor.
This maximum peak current can be calculated as follows:
where t
on
is the “on” time of the power switch and
For additional information about the inductor, see the inductor
section in the “EXTERNAL COMPONENTS” section of this
data sheet.
I
p
(
max
)
+ I
Load
(
max
)
)
ǒ
V
in
* V
out
Ǔ
t
on
2L
t
on
+
V
out
V
in
x
1.0
f
osc
4. Inductor Selection (L1)
A. Use the inductor selection guide shown in Figure 20.
B. From the selection guide, the inductance area
intersected by the 15 V line and 0.4 A line is 330.
C. Inductor value required is 330 mH. From Table 2, choose
an inductor from any of the listed manufacturers.
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Procedure (Fixed Output Voltage Version) (continued) In order to simplify the switching regulator design, a step−by−step
design procedure and example is provided.
Procedure Example
5. Output Capacitor Selection (C
out
)
A. Since the LM2574 is a forward−mode switching regulator
with voltage mode control, its open loop 2−pole−1−zero
frequency characteristic has the dominant pole−pair
determined by the output capacitor and inductor values. For
stable operation and an acceptable ripple voltage,
(approximately 1% of the output voltage) a value between
100 mF and 470 mF is recommended.
B. Due to the fact that the higher voltage electrolytic capacitors
generally have lower ESR (Equivalent Series Resistance)
numbers, the output capacitor’s voltage rating should be at
least 1.5 times greater than the output voltage. For a 5.0 V
regulator, a rating at least 8.0 V is appropriate, and a 10 V
or 16 V rating is recommended.
5. Output Capacitor Selection (C
out
)
A. C
out
= 100 mF to 470 mF standard aluminium electrolytic.
B. Capacitor voltage rating = 20 V.
Procedure (Adjustable Output Version: LM2574−ADJ)
Procedure Example
Given Parameters:
V
out
= Regulated Output Voltage
V
in(max)
= Maximum DC Input Voltage
I
Load(max)
= Maximum Load Current
Given Parameters:
V
out
= 24 V
V
in(max)
= 40 V
I
Load(max)
= 0.4 A
1. Programming Output Voltage
To select the right programming resistor R1 and R2 value (see
Figure 2) use the following formula:
where V
ref
= 1.23 V
Resistor R1 can be between 1.0 kW and 5.0 kW. (For best
temperature coefficient and stability with time, use 1% metal
film resistors).
V
out
+ V
ref
ǒ
1.0 )
R2
R1
Ǔ
R2 + R1
ǒ
V
out
V
ref
* 1.0
Ǔ
1. Programming Output Voltage (selecting R1 and R2)
Select R1 and R2 :
V
out
= 1.23 Select R1 = 1.0 kW
R2 = 18.51 kW, choose a 18.7 kW metal film resistor.
ǒ
1.0 )
R2
R1
Ǔ
R2 + R1
ǒ
V
out
V
ref
* 1.0
Ǔ
+ 1.0 k
ǒ
10 V
1.23 V
* 1.0
Ǔ
2. Input Capacitor Selection (C
in
)
To prevent large voltage transients from appearing at the input
and for stable operation of the converter, an aluminium or
tantalum electrolytic bypass capacitor is needed between the
input pin +V
in
and ground pin Gnd. This capacitor should be
located close to the IC using short leads. This capacitor should
have a low ESR (Equivalent Series Resistance) value.
For additional information see input capacitor section in the
“EXTERNAL COMPONENTS” section of this data sheet.
2. Input Capacitor Selection (C
in
)
A 22 mF aluminium electrolytic capacitor located near the
input and ground pin provides sufficient bypassing.
3. Catch Diode Selection (D1)
A. Since the diode maximum peak current exceeds the
regulator maximum load current the catch diode current
rating must be at least 1.2 times greater than the maximum
load current. For a robust design, the diode should have a
current rating equal to the maximum current limit of the
LM2574 to be able to withstand a continuous output short.
B. The reverse voltage rating of the diode should be at least
1.25 times the maximum input voltage.
3. Catch Diode Selection (D1)
A. For this example, a 1.0 A current rating is adequate.
B. Use a 50 V MBR150 Schottky diode or any suggested
fast recovery diodes in Table 1.
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Procedure (Adjustable Output Version: LM2574−ADJ)
Procedure Example
4. Inductor Selection (L1)
A. Use the following formula to calculate the inductor Volt x
microsecond [V x ms] constant:
B. Match the calculated E x T value with the corresponding
number on the vertical axis of the Inductor Value Selection
Guide shown in Figure 23. This E x T constant is a measure
of the energy handling capability of an inductor and is
dependent upon the type of core, the core area, the number
of turns, and the duty cycle.
C. Next step is to identify the inductance region intersected by
the E x T value and the maximum load current value on the
horizontal axis shown in Figure 27.
D. From the inductor code, identify the inductor value. Then
select an appropriate inductor from Table 2. The inductor
chosen must be rated for a switching frequency of 52 kHz
and for a current rating of 1.15 x I
Load
. The inductor current
rating can also be determined by calculating the inductor
peak current:
where t
on
is the “on” time of the power switch and
For additional information about the inductor, see the inductor
section in the “External Components” section of this data
sheet.
t
on
+
V
out
V
in
x
1.0
f
osc
I
p
(
max
)
+ I
Load
(
max
)
)
ǒ
V
in
* V
out
Ǔ
t
on
2L
ExT+ (V
in
* V
out
)
V
out
V
in
x
10
6
F
[
Hz
]
ƪ
Vxms
ƫ
4. Inductor Selection (L1)
A.
B.
C. I
Load(max)
= 0.4 A
Inductance Region = 1000
D. Proper inductor value = 1000 mH
Choose the inductor from Table 2.
ExT+ (40 * 24) x
24
40
x
1000
52
+ 105
ƪ
Vxms
ƫ
ExT+ 185
ƪ
Vxms
ƫ
Calculate E x T
ƪ
Vxms
ƫ
constant :
5. Output Capacitor Selection (C
out
)
A. Since the LM2574 is a forward−mode switching regulator with
voltage mode control, its open loop 2−pole−1−zero frequency
characteristic has the dominant pole−pair determined by the
output capacitor and inductor values.
For stable operation, the capacitor must satisfy the following
requirement:
B. Capacitor values between 10 mF and 2000 mF will satisfy the
loop requirements for stable operation. To achieve an
acceptable output ripple voltage and transient response, the
output capacitor may need to be several times larger than the
above formula yields.
C. Due to the fact that the higher voltage electrolytic capacitors
generally have lower ESR (Equivalent Series Resistance)
numbers, the output capacitor’s voltage rating should be at
least 1.5 times greater than the output voltage. For a 5.0 V
regulator, a rating of at least 8.0 V is appropriate, and a 10 V
or 16V rating is recommended.
C
out
w 13,300
V
in
(
max
)
V
out
xL
ƪ
mH
ƫ
ƪ
mF
ƫ
5. Output Capacitor Selection (C
out
)
A.
To achieve an acceptable ripple voltage, select
C
out
= 100 mF electrolytic capacitor.
C
out
w 13,300 x
40
24 x 1000
+ 22.2 mF

LM2574N-ADJ

Mfr. #:
Manufacturer:
ON Semiconductor
Description:
IC REG MULT CONFG ADJ 500MA 8DIP
Lifecycle:
New from this manufacturer.
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