16
LT1507
APPLICATIONS INFORMATION
WUU
U
The circuit in Figure 6 will allow operation at light loads
with low input voltages. It uses a small PNP to charge the
boost capacitor (C2) and an extra diode (D3) to complete
the power path
from V
SW
to the boost capacitor. Note that
the diodes have been changed to Schottky BAT85s to
optimize low voltage operation. Figure 5 shows that with
the added PNP, minimum load current can be reduced to
6mA and still guarantee proper start-up with 4.7V input.
problems. For low input voltage, high sync frequency
applications, the circuit shown in Figure 7 can be used to
generate an external slope compensation ramp that elimi-
nates subharmonic oscillation. See Frequency Compen-
sation section for a discussion of an entirely different
cause of subharmonic switching before assuming that the
cause is insufficient slope compensation. Application Note
19 has more details on the theory of slope compensation.
V
IN
V
SW
SENSE
BOOST
GND V
C
LT1507-3.3
D2
BAT85
C2
0.22µF
L1
D1
1N5818
C
C
+
C1
+
INPUT
LT1507 • F06
D3
BAT85
Q1
2N3906
V
OUT
= 3.3V
Figure 6. Adding a Small PNP to Reduce Minimum
Start-Up Voltage
SYNCHRONIZING
The LT1507 SYNC pin is used to synchronize the internal
oscillator to an external signal. It is directly logic compat-
ible and can be driven with any signal between 10% and
90% duty cycle. The synchronizing range is equal to
initial
operating frequency up to 1MHz (above 700kHz external
slope compensation may be needed). This means that
minimum practical sync frequency is equal to the worst-
case
high
self-oscillating frequency (560kHz) not the
typical operating frequency of 500kHz. Caution should be
used when synchronizing above 700kHz because at higher
sync frequencies, the amplitude of the internal slope
compensation used to prevent subharmonic switching is
reduced. This type of subharmonic switching only occurs
at input voltages less than twice the output voltage and
shows up as alternating pulse widths at the switch node.
It does not cause the regulator to lose regulation, but
switch frequency content down to 100kHz may be objec-
tionable. Higher inductor values will tend to eliminate
SYNC
V
SW
GND V
C
LT1507
+
V
OUT
LT1507 • F07
R
C
470
R
S
5.2k
C
S
1000pF
C
C
2000pF
Figure 7. Adding External Slope Compensation for High
Sync Frequencies
External Slope Compensation Ramp
The LT1507 is a current mode switching regulator and
therefore, it requires something called “slope compensa-
tion”
when operated above 50% duty cycle in continuous
mode.
This condition occurs when input voltage is less
than twice output voltage. Slope compensation adds a
ramp to the switch current sense signal generated on the
chip during switch ON time. Typically the ramp is gener-
ated from a portion of the internal oscillator waveform. In
the LT1507, the ramp is arranged to be zero until the
oscillator waveform reaches about 40% of its final value.
This minimizes the total amount of ramp added to switch
current. The reason for doing it this way is that the ramp
subtracts from switch current limit, so that switch current
limit would be considerably lower at high duty cycle
compared to low duty cycle if the ramp existed at all duty
cycles. By starting the ramp at the 40% point, changes in
current limit are minimized. No ramp is needed when
operating below 50% duty cycle.
Problems can occur with this technique if the regulator is
used with a combination of high external sync frequency
and more than 50% duty cycle. The basic sync function
17
LT1507
APPLICATIONS INFORMATION
WUU
U
For V
IN
= 4.7, V
OUT
= 3.3V, f = 1MHz, L = 5µH and DC
S
= 25%:
VmV
P-P
−−
=
(. .)( . )
.
66 47 1 025
2 1 10 5 10 1 8
71
66
To avoid small values of R
S
, the compensation capacitor (C
C
)
should be made as small as possible. 2000pF will work in
most situations. If we increase V
PP
to 90mV for a little
cushion, R
S
will be:
Rk
CpF
S
=
()
()
=
()
()
=
()(. )(. )
.
.
5 0 25 0 75
0 09 2 10 1 10
52
20
2 1 10 5200
612
96
6
π
THERMAL CALCULATIONS
Power dissipation in the LT1507 chip comes from four
sources: switch DC loss, switch AC loss, boost circuit
current and input quiescent current. The formulas below
show how to calculate each of these losses. These formu-
las assume continuous mode operation, so they should
not be used for calculating efficiency at light load currents.
Switch loss:
P
RI V
V
ns I V f
SW
SW OUT OUT
IN
OUT IN
=+
()()
()()()
2
16
Boost current loss:
P
V
V
I
BOOST
OUT
IN
OUT
=+
2
0 008
75
.
Quiescent current loss:
PV V
Q IN OUT
=+(. ) (. )0 003 0 005
R
SW
= Switch resistance ( 0.4)
16ns = Equivalent switch current/voltage overlap time
f = Switching frequency
works by prematurely tripping the oscillator before it
reaches its normal peak value. For instance, if the oscilla-
tor is synchronized at twice its nominal frequency, oscil-
lator amplitude will drop by half. A ramp which previously
started at the 40% point now starts at the 80% point! This
effectively blocks slope compensation and the regulator
may respond with fluctuating pulse widths, a “phase
oscillation” if you will. The regulator output stays in
regulation but subharmonic frequencies are generated at
the switch node.
The solution to this problem is to generate an external
ramp that replaces the missing internal ramp. As it turns
out, this is not difficult if the sync signal can be arranged
to have a fairly low duty cycle (< 35%). The ramp is created
by AC coupling a resistor from the sync signal to the
compensation capacitor as shown in Figure 7. This gener-
ates a negative ramp on the V
C
pin during switch ON time
that emulates the missing internally generated ramp.
Amplitude of the ramp should be about 100mV to 200mV
peak-to-peak. The formulas for calculating the values of
R
S
and C
S
are shown below. Note that the C
S
value is
unimportant as long as it exceeds the value given. The
formula assures that the impedance of C
S
will be small
compared to R
S
.
R
VDCDC
VCf
C
fR
S
SYNC S S
C
S
S
=
>
()( )
()()
()( )
1
20
2
P-P
π
V
SYNC
= Peak-to-peak value of sync signal
DC
S
= Duty cycle
of incoming sync signal
V
P-P
= Desired amplitude of ramp
f = Sync frequency
Theoretical minimum amplitude for the ramp, assuming
no internal ramp, is:
V
VVDC
fLg
OUT IN S
mP
P-P
−−()()
()()( )
21
2
g
mP
= Transconductance from V
C
pin to switch current
(1.8A/V for the LT1507).
18
LT1507
APPLICATIONS INFORMATION
WUU
U
Example: with V
IN
= 5V, V
OUT
= 3.3V, I
OUT
= 1A;
P
W
PW
PW
SW
BOOST
Q
=+
()
()()
()
=+=
=
+
=
=+ =
(.)()(.)
...
(.)
..
(. ) .(. ) .
04 1 33
5
16 10 1 5 500 10
026 004 03
33
5
0 008
1
75
0 046
5 0 003 3 3 0 005 0 032
2
93
2
Total power dissipation is 0.3 + 0.046 + 0.032 = 0.38W.
Thermal resistance for the LT1507 packages is influenced
by the presence of internal or backside planes. With a full
plane under the SO package, thermal resistance will be
about 120°C/W. No plane will increase resistance to about
150°C/W. To calculate die temperature, use the proper
thermal resistance number for the desired package and
add in worst-case ambient temperature;
T
J
= T
A
+ θ
JA
(P
TOT
)
With the S8 package (θ
JA
= 120°C/W) at an ambient
temperature of 70°C;
T
J
= 70 + 120(0.38) = 116°C
FREQUENCY COMPENSATION
The LT1507 uses a “current mode” architecture to help
alleviate phase shift created by the inductor. The basic
connections are shown in Figure 9. Gain of the power stage
can be modeled as 1.8A/V transconductance from the V
C
pin voltage to current delivered to the output. This is
shown in Figure 8 where the transconductance from V
C
pin to inductor current is essentially flat from 50Hz to
50kHz and phase shift is minimal in the important loop
unity-gain band of 1kHz to 50kHz. Inductor variation from
3µH to 20µH will have very little effect on these curves.
Overall gain from the V
C
pin to output is then modeled as
the product of 1.8A/V transconductance multiplied by the
complex impedance of the load in parallel with the output
capacitor model.
The error amplifier can be modeled as a transconductance
of 2000µmho, with an output impedance of 200k in
FREQUENCY (Hz)
GAIN-V
C
PIN TO INDUCTOR CURRENT (A/V)
2.0
1.5
1.0
0.5
0
PHASE-V
C
PIN TO INDUCTOR CURRENT (C°)
80
40
0
40
–80
10 1k 10k 100k
LT1507 • F08
100
GAIN (A/V)
PHASE
V
OUT
= 3.3V
I
OUT
= 250mA
V
IN
= 5V
L = 10µH
Figure 8. Phase and Gain from V
C
Pin Voltage
to Inductor Current
POWER STAGE
g
m
= 1.8A/V
ERROR AMPLIFIER
g
m
= 2000µho
200k
2.42V
LT1507
R
C
C
C
C
F
GND V
C
V
SW
L1
F
B
R1
R2
ESR
+
OUTPUT
1507 • F09
+
C1
12pF
Figure 9. Small-Signal Model for Loop Stability Analysis
parallel with 12pF. In all practical applications, the com-
pensation network from V
C
pin to ground has a much
lower impedance than the output impedance of the ampli-
fier at frequencies above 500Hz. This means that the error
amplifier characteristics themselves do not contribute
excess phase shift to the loop and the phase/gain charac-
teristics of the error amplifier section are completely
controlled by the external compensation network.
The complete small-signal model is shown in Figure 9. R1
and R2 are the divider used to set output voltage. These are
internal on the fixed voltage LT1507-3.3 with R1 = 1.8k
and R2 = 5k. R
C
, C
C
and C
F
are external compensation

LT1507IS8-3.3#TRPBF

Mfr. #:
Manufacturer:
Analog Devices / Linear Technology
Description:
Switching Voltage Regulators 500kHz Mono Buck Mode Sw Reg
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New from this manufacturer.
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