LM2575, NCV2575
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10
Procedure (Fixed Output Voltage Version) In order to simplify the switching regulator design, a stepbystep design
procedure and example is provided.
Procedure
Example
Given Parameters:
V
out
= Regulated Output Voltage (3.3 V, 5.0 V, 12 V or 15 V)
V
in(max)
= Maximum DC Input Voltage
I
Load(max)
= Maximum Load Current
Given Parameters:
V
out
= 5.0 V
V
in(max)
= 20 V
I
Load(max)
= 0.8 A
1. Controller IC Selection
According to the required input voltage, output voltage and
current, select the appropriate type of the controller IC output
voltage version.
1. Controller IC Selection
According to the required input voltage, output voltage,
current polarity and current value, use the LM25755
controller IC
2. Input Capacitor Selection (C
in
)
To prevent large voltage transients from appearing at the input
and for stable operation of the converter, an aluminium or
tantalum electrolytic bypass capacitor is needed between the
input pin +V
in
and ground pin GND. This capacitor should be
located close to the IC using short leads. This capacitor should
have a low ESR (Equivalent Series Resistance) value.
2. Input Capacitor Selection (C
in
)
A 47 mF, 25 V aluminium electrolytic capacitor located near
to the input and ground pins provides sufficient bypassing.
3. Catch Diode Selection (D1)
A. Since the diode maximum peak current exceeds the
regulator maximum load current the catch diode current
rating must be at least 1.2 times greater than the maximum
load current. For a robust design the diode should have a
current rating equal to the maximum current limit of the
LM2575 to be able to withstand a continuous output short
B. The reverse voltage rating of the diode should be at least
1.25 times the maximum input voltage.
3. Catch Diode Selection (D1)
A. For this example the current rating of the diode is 1.0 A.
B. Use a 30 V 1N5818 Schottky diode, or any of the
suggested fast recovery diodes shown in the Table 4.
4. Inductor Selection (L1)
A. According to the required working conditions, select the
correct inductor value using the selection guide from
Figures 17 to 21.
B. From the appropriate inductor selection guide, identify the
inductance region intersected by the Maximum Input
Voltage line and the Maximum Load Current line. Each
region is identified by an inductance value and an inductor
code.
C. Select an appropriate inductor from the several different
manufacturers part numbers listed in Table 1 or Table 2.
When using Table 2 for selecting the right inductor the
designer must realize that the inductor current rating must
be higher than the maximum peak current flowing through
the inductor. This maximum peak current can be calculated
as follows:
where t
on
is the “on” time of the power switch and
For additional information about the inductor, see the
inductor section in the “External Components” section of
this data sheet.
I
p(max)
+ I
Load(max)
)
ǒ
V
in
V
out
Ǔ
t
on
2L
t
on
+
V
out
V
in
x
1
f
osc
4. Inductor Selection (L1)
A. Use the inductor selection guide shown in Figures 17
to 21.
B. From the selection guide, the inductance area intersected
by the 20 V line and 0.8 A line is L330.
C. Inductor value required is 330 mH. From the Table 1 or
Table 2, choose an inductor from any of the listed
manufacturers.
LM2575, NCV2575
http://onsemi.com
11
Procedure (Fixed Output Voltage Version) (continued)In order to simplify the switching regulator design, a stepbystep design
procedure and example is provided.
Procedure Example
5. Output Capacitor Selection (C
out
)
A. Since the LM2575 is a forwardmode switching regulator
with voltage mode control, its open loop 2pole2zero
frequency characteristic has the dominant polepair
determined by the output capacitor and inductor values. For
stable operation and an acceptable ripple voltage,
(approximately 1% of the output voltage) a value between
100 mF and 470 mF is recommended.
B. Due to the fact that the higher voltage electrolytic capacitors
generally have lower ESR (Equivalent Series Resistance)
numbers, the output capacitor’s voltage rating should be at
least 1.5 times greater than the output voltage. For a 5.0 V
regulator, a rating at least 8V is appropriate, and a 10 V or
16 V rating is recommended.
5. Output Capacitor Selection (C
out
)
A. C
out
= 100 mF to 470 mF standard aluminium electrolytic.
B. Capacitor voltage rating = 16 V.
Procedure (Adjustable Output Version: LM2575Adj)
Procedure Example
Given Parameters:
V
out
= Regulated Output Voltage
V
in(max)
= Maximum DC Input Voltage
I
Load(max)
= Maximum Load Current
Given Parameters:
V
out
= 8.0 V
V
in(max)
= 12 V
I
Load(max)
= 1.0 A
1. Programming Output Voltage
To select the right programming resistor R1 and R2 value (see
Figure 14) use the following formula:
Resistor R1 can be between 1.0 k and 5.0 kW. (For best
temperature coefficient and stability with time, use 1% metal
film resistors).
V
out
+ V
ref
ǒ
1 )
R2
R1
Ǔ
R2 + R1
ǒ
V
out
V
ref
1
Ǔ
where V
ref
= 1.23 V
1. Programming Output Voltage (selecting R1 and R2)
Select R1 and R2:
R2 = 9.91 kW, choose a 9.88 k metal film resistor.
R2 + R1
ǒ
V
out
V
ref
* 1
Ǔ
+ 1.8 k
ǒ
8.0 V
1.23 V
* 1
Ǔ
V
out
+ 1.23
ǒ
1 )
R2
R1
Ǔ
Select R1 = 1.8 kW
2. Input Capacitor Selection (C
in
)
To prevent large voltage transients from appearing at the input
and for stable operation of the converter, an aluminium or
tantalum electrolytic bypass capacitor is needed between the
input pin +V
in
and ground pin GND This capacitor should be
located close to the IC using short leads. This capacitor should
have a low ESR (Equivalent Series Resistance) value.
For additional information see input capacitor section in the
“External Components” section of this data sheet.
2. Input Capacitor Selection (C
in
)
A 100 mF aluminium electrolytic capacitor located near the
input and ground pin provides sufficient bypassing.
3. Catch Diode Selection (D1)
A. Since the diode maximum peak current exceeds the
regulator maximum load current the catch diode current
rating must be at least 1.2 times greater than the maximum
load current. For a robust design, the diode should have a
current rating equal to the maximum current limit of the
LM2575 to be able to withstand a continuous output short.
B. The reverse voltage rating of the diode should be at least
1.25 times the maximum input voltage.
3. Catch Diode Selection (D1)
A. For this example, a 3.0 A current rating is adequate.
B. Use a 20 V 1N5820 or MBR320 Schottky diode or any
suggested fast recovery diode in the Table 4.
LM2575, NCV2575
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12
Procedure (Adjustable Output Version: LM2575Adj) (continued)
Procedure Example
4. Inductor Selection (L1)
A. Use the following formula to calculate the inductor Volt x
microsecond [V x ms] constant:
B. Match the calculated E x T value with the corresponding
number on the vertical axis of the Inductor Value Selection
Guide shown in Figure 21. This E x T constant is a measure
of the energy handling capability of an inductor and is
dependent upon the type of core, the core area, the number
of turns, and the duty cycle.
C. Next step is to identify the inductance region intersected by
the E x T value and the maximum load current value on the
horizontal axis shown in Figure 21.
D. From the inductor code, identify the inductor value. Then
select an appropriate inductor from the Table 1 or Table 2.
The inductor chosen must be rated for a switching
frequency of 52 kHz and for a current rating of 1.15 x I
Ioad
.
The inductor current rating can also be determined by
calculating the inductor peak current:
where t
on
is the “on” time of the power switch and
For additional information about the inductor, see the
inductor section in the “External Components” section of
this data sheet.
ExT+
ǒ
V
in
V
out
Ǔ
V
out
V
on
x
10
6
F[Hz]
[V x ms]
I
p(max)
+ I
Load(max)
)
ǒ
V
in
V
out
Ǔ
t
on
2L
t
on
+
V
out
V
in
x
1
f
osc
4. Inductor Selection (L1)
A. Calculate E x T [V x ms] constant:
B. E x T = 51 [V x ms]
C. I
Load(max)
= 1.0 A
Inductance Region = L220
D. Proper inductor value = 220 mH
Choose the inductor from the Table 1 or Table 2.
ExT+
ǒ
12
8.0
Ǔ
x
8.0
12
x
1000
52
+ 51 [V x ms]
5. Output Capacitor Selection (C
out
)
A. Since the LM2575 is a forwardmode switching regulator
with voltage mode control, its open loop 2pole2zero
frequency characteristic has the dominant polepair
determined by the output capacitor and inductor values.
For stable operation, the capacitor must satisfy the
following requirement:
B. Capacitor values between 10 mF and 2000 mF will satisfy
the loop requirements for stable operation. To achieve an
acceptable output ripple voltage and transient response, the
output capacitor may need to be several times larger than
the above formula yields.
C. Due to the fact that the higher voltage electrolytic capacitors
generally have lower ESR (Equivalent Series Resistance)
numbers, the output capacitor’s voltage rating should be at
least 1.5 times greater than the output voltage. For a 5.0 V
regulator, a rating of at least 8V is appropriate, and a 10 V
or 16 V rating is recommended.
C
out
w 7.785
V
in(max)
V
out
xL[μH]
[μF]
5. Output Capacitor Selection (C
out
)
A.
To achieve an acceptable ripple voltage, select
C
out
= 100 mF electrolytic capacitor.
C
out
w 7.785
12
8.220
+ 53 μF

LM2575D2T-ADJG

Mfr. #:
Manufacturer:
ON Semiconductor
Description:
Switching Voltage Regulators 1A 1.23-37V ADJ Buck PWM
Lifecycle:
New from this manufacturer.
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