S ECOND-GENERATION POWER FACTOR CONTROLLER
LX1562/1563
PRODUCT DATABOOK 1996/1997
19
Copyright © 1996
Rev. 1.3a 8/30
P RODUCTION DATA SHEET
APPLICATION INFORMATION
INDUCTOR DESIGN (continued)
Step 2: Choose a core with higher K
g
than the one calculated in
Step 1.
K
g
/core = k
where: k Winding coefficient (typ. k=0.4)
A
W
Bobbin window area
A
E
Effective core area
l
W
Mean length per turn
K
g
factor for TDK PQ2625:
A
W
= 47.7mm
2
A
E
= 118mm
2
l
W
= 56.2mm
K
g
= 0.4 (mm)
5
= 4.7
*
10
-12
m
5
A
W
A
E
2
l
W
(47.7) (118)
2
56.2
Step 3: Determine number of turns.
N =
N = = 61 turns
A
WIRE
= k = 0.4 = 0.31mm
2
= 480mil
2
choose #22 AWG with r = 0.0165/feet resistance.
R
W
= N
*
l
w
*
r
R
W
= 0.185
L I
LP
B A
E
450
*
10
-6
*
2.4
0.15
*
118
*
10
-6
A
W
N
47.7
61
Step 4: Calculate air gap.
l
g
=
l
q
= = 0.122cm = 48 mil
µ
O
N
2
A
E
L
4π
*
10
-7
*
(61)
2
*
118
*
10
-6
450
*
10
-6
CURRENT SENSE RESISTOR
Current sense resistor, R6 is selected using the minimum multi-
plier output clamp voltage and the maximum inductor peak
current such that:
R6 = = = 0.45
Power dissipation is approximated by:
P
R
I
2 (MAX)
2
(1 - D'
MIN
), where D'
MIN
= 1 -
P
R
(2.4)
2
(1 - 0.61) = 0.374
Select THREE 1.3, ¼W carbon comp resistors in parallel.
V
CLAMP(MIN)
I
L (MAX)
1.1
2.4
1
6
2 V
AC(MIN)
V
BOOST
1
6
R2
R1 + R2
MULTIPLIER COMPONENT SELECTION
Calculate R1 & R2 resistor values such that under low line AC input
the multiplier output is lower than the minimum clamp voltage.
*
2 V
AC (MIN)
*
K
*
(V
EA0 (MAX)
- V
REF
) < V
CLAMP (MIN)
where: K Mult. Gain
V
EA)(MAX)
Maximum error amp output where
multiplier is still in linear range.
This voltage is 3.5V.
For K = 0.65 & V
CLAMP (MIN)
= 1.1V, the ratio of R1/R2 is:
> 83
Assuming R1 is selected to be:
* R1 = 2.2M (1%)
R2 = = 26.4k (1%) select R
2
= 26.7k (1%)
* For high input applications such as 277V, R1 must be divided
into two resistors in series to meet the maximum rated voltage of
the resistors.
To improve THD further (typ. 2-3%), a high value resistor can
be connected from the supply voltage to this pin to allow an
increase in the switch on-time at the zero crossing by adding an
effective offset at the multiplier output.
ERROR AMPLIFIER COMPONENT SELECTION
Boost voltage is programmed with R7 & R8 resistor dividers using
the following equation:
= -1,
assuming that the product of R7 and the E.A. input bias current
does not cause significant error in the output voltage setting.
Assuming R7 = 1M
(for output voltage of higher than 250V,
two resistors may be added in series to meet the voltage
requirement of the resistor.)
V
ERROR
(10
6
) (0.5 * 10
-6
) = 0.5V, which is < 0.25% of the
output voltage.
Calculating R8:
R8 = = 11k (1%)
Worst case output tolerance is the total of ±3.75% which is the sum
of ±1.5% (Ref), ±2% (resistor dividers), and ±0.25% (E.A. input
bias current).
R7
R8
V
BOOST
V
REF
R7
V
BOOST
V
REF
- 1
R1
R2
2.2M
83
OBSOLETE PRODUCT
NOT RECOMMENDED FOR NEW DESIGNS
S ECOND-GENERATION POWER FACTOR CONTROLLER
LX1562/1563
PRODUCT DATABOOK 1996/1997
Copyright © 1996
Rev. 1.3a 8/30
20
P
RODUCTION DATA SHEET
APPLICATION INFORMATION
ERROR AMPLIFIER COMPONENT SELECTION (continued)
Capacitor C5 is primarily selected to reject the output ripple
associated with twice the line frequency. For a 40dB ripple
rejection:
C5 where f
l
= 2x line frequency
C5 = 0.062µF, Select C5 = 0.1µF
Resistor R9 can be used to improve load transient response at the
cost of loosing 1 or 2% of load regulation. The value of this resistor
should be much greater than R8:
R9 = 620k
One way of achieving desired load transient response without
resorting to a complex mathematical model of the converter, is to
dynamically switch the output load and empirically find the
compensation network. The value of resistor R9 is selected using
the method shown in Figure 34.
FIGURE 34 — LOAD TRANSIENT RESPONSE CIRCUIT
I
DETECT
COMPONENT SELECTION
Figure 35 shows voltage envelope generated by flyback voltage
across I
DET
winding:
Select turns ratio n such that,
n =
n = = 0.11
I
DET
winding turns are
selected to be 7T.
and R4 resistor:
< R4 < 500k
< R4 < 500k, or 8.4k < R4 < 500k
Select R4 = 22k
2 V
AC (MIN)
I
ST (MAX)
2
*
100
0.3
*
10
-3
2 V
AC (MIN)
R3
- I
ST
V
ST
5V
V
BOOST
- 2 V
AC (MAX)
5V
230 - 2
*
130
SUPPLY VOLTAGE
Resistor R3 must be selected such that it ensures converter start-
up at low line and is rated for high line power dissipation.
R3 < where: I
ST
Maximum start-up
current
V
ST
Start-up voltage
T
ST(MAX)
Maximum start-up
time at AC power-on
R3 < = 466k
R3 > 4 V
AC (MAX)
(to keep power dissipation below 0.5W)
R3 > 68k , select R3 = 120k.
Start-up time of converter is given by:
T
ST (MAX)
C2
for our application this will be 25ms/µF.
I
OP
* t
V
MIN
The start-up capacitor is selected such that capacitor discharge
time is always longer than the time it takes for the bootstrap
voltage to reach above the minimum start-up threshold of the IC.
C3 < where: I
OP
Maximum dynamic
supply current of the IC
t Rise time of the
bootstrap voltage
V
MIN
Minimum hysteresis
voltage
(4V for 1562,
1.7V for 1563)
C3 < = 29µF
Select C3 = 33µF.
Start-up time is approximately 0.8 seconds.
The auxiliary winding turns are selected such that it provides 15V
of operating voltage.
N
S
N
P
* = 61 * = 4T
However, in this example I
DETECT
winding is used to power the IC
which eliminates the need for a third winding. This is possible
since the internal clamping of the output drive limits the gate
drive voltage to 14V (typ.) if the supply voltage exceeds this limit.
10
*
10
-3
*
10
*
10
-3
4
V
S
V
O
V
S
V
O
100
2π f
l
R7
100
2π
*
120
*
2.2
*
10
6
V
BOOST
R
L
10Hz
50% D.C.
Min.
Load
n
*
V
BOOST
3
*
10
-3
0.11
*
230
3
*
10
-3
n
(V
BOOST
- V
AC
)
n
V
AC
FIGURE 35 — FLYBACK VOLTAGE
ACROSS I
DET
WINDING
OBSOLETE PRODUCT
NOT RECOMMENDED FOR NEW DESIGNS
S ECOND-GENERATION POWER FACTOR CONTROLLER
LX1562/1563
PRODUCT DATABOOK 1996/1997
21
Copyright © 1996
Rev. 1.3a 8/30
P RODUCTION DATA SHEET
APPLICATION INFORMATION
POWER MOSFET SELECTION
The voltage rating of MOSFET and rectifier must be higher than
the maximum value of the output voltage.
V
DS
1.2 V
O MAX
V
DS
282V
The RMS current can be approximated by multiplying the RMS
current at the peak of the line by 0.7.
I
RMS
= 0.7 I
LP
D/3 D On-time duty cycle
D = 0.39 at V
AC
= 100V
I
LP
= 2.4A
I
RMS
= (0.7)(2.4)(.39/3) = 0.61A
R
DS
P
DC
allowable power I
RMS
/triangle = I
LP
D/3
dissipation.
R
DS
= 1.6
IRF730 with R
DS
= 1
and V
DS
= 400V meets the above
requirements.
P
DC
I
RMS
2
1
0.61
I
LP
D
INPUT RECTIFIER AND CAPACITOR SELECTION
The current through each diode is a half-wave rectified sine wave.
The maximum current happens at minimum line with a peak
value of 1.2A.
I
AVE
= = = 0.38A
choose 1N4004 with 1A rating.
P
DISS
= (I
AVE
) (V
F
) = 0.38 x 0.9 = 0.344W
T
J
= T
A
+ P
D
x θ
JA
assuming θ
JA
= 65°C/W for 1/8"
lead length.
T
J
= 80 + (.344)(65) = 102°C
I
PEAK
π
1.2
π
Assuming ϕ is the percentage of allowable input current ripple,
C1 can be calculated using the following equations:
R
EFF
=
C1 f
SW
Switching frequency
of inductor current
at peak input voltage.
if ϕ = 3%
R
EFF
= = 117
C1 = 0.9µF
choose 1µF, 250V capacitor.
2 P
O
η I
P
2
1
ϕ 2π R
EFF
f
SW
2 x 80
(.95)(1.2)
2
1
(.03)(2π)(117)(50000)
OUTPUT CAPACITOR SELECTION
There are mainly two criteria for selecting the output capacitor:
A large enough capacitance to maintain a low ripple voltage, and
a low ESR value in order to prevent high power dissipation due
to RMS currents.
The output capacitance can be approximated from the following
equation:
C6 where: I
DC
DC output current
DV Output ripple
I
DC
= = 0.348A
assuming 5% peak to peak ripple,
C6 = 81µF
choose C6 = 100µF.
I
DC
2π f
LINE
V
80
230
0.348
2π (60) (11.5)
OBSOLETE PRODUCT
NOT RECOMMENDED FOR NEW DESIGNS

LX1562IM

Mfr. #:
Manufacturer:
Microchip / Microsemi
Description:
IC PFC CONTROLLER 8DIP
Lifecycle:
New from this manufacturer.
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