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LTC1062CN8#PBF

P1-P3P4-P6P7-P9P10-P12P13-P15P16-P16
7
LTC1062
1062fd
Divide By 1, 2, 4 (Pin 4)
By connecting Pin 4 to V
+
, to mid supplies or to V
–
, the
clock frequency driving the internal switched capacitor
network is the oscillator frequency divided by 1, 2, 4
respectively. Note that the f
CLK
/f
C
ratio of 100:1 is with
respect to the internal clock generator output frequency.
The internal divider is useful for applications where octave
tuning is required. The ÷2 threshold is typically ±1V from
the mid supply voltage.
Transient Response
Figure 3 shows the LTC1062 response to a 1V input step.
Filter Noise
The filter wideband RMS noise is typically 100µV
RMS
for
±5V supply and it is nearly independent from the value of
the cutoff frequency. For single 5V supply the RMS noise
is 80µV
RMS
. Sixty-two percent of the wideband noise is in
the passband, that is from DC to f
C
. The noise spectral
density, unlike conventional active filters, is nearly zero for
frequencies below 0.1 • f
C
. This is shown in the Typical
Performance Characteristics section. Table 2 shows the
LTC1062 RMS noise for different noise bandwidths.
Table 2
NOISE BW RMS NOISE (V
S
= ±5V)
DC – 0.1 • f
C
2µV
DC – 0.25 • f
C
8µV
DC – 0.5 • f
C
20µV
DC – 1 • f
C
62µV
DC – 2 • f
C
100µV
200mV/VERT DIV
50ms/HORIZ DIV, f
C
= 10Hz
5ms/HORIZ DIV, f
C
= 100Hz
0.5ms/HORIZ DIV, f
C
= 1kHz
1
2πRC
f
C
1.62
=
1
2πRC
f
C
1.94
=
1
2πRC
f
C
2.11
=
Figure 3. Step Response to a 1V Peak Input Step
APPLICATIO S I FOR ATIO
WUUU
8
LTC1062
1062fd
AC Coupling an External CMOS Clock Powered
from a Single Positive Supply, V
+
FB
AGND
V
–
DIVIDER
RATIO
B
OUT
OUT
V
+
C
OSC
1
2
3
4
8
7
6
5
LTC1062
0.01µF
V
+
0
1062 TA03
C
V
IN
V
+
100k
V
OUT
V
–
Adding an External (R1, C1) to Eliminate the Clock Feedthrough and
to Improve the High Frequency Attenuation Floor
FB
AGND
V
–
DIVIDER
RATIO
B
OUT
OUT
V
+
C
OSC
1
2
3
4
8
7
6
5
LTC1062
V
OUT
V
+
f
CLK
1062 TA04
C
C1
0.01C
V
IN
R
V
–
R1
10R
–
+
EXTERNAL
BUFFER
Filtering AC Signals from High DC Voltages
FB
AGND
V
–
DIVIDER
RATIO
B
OUT
OUT
V
+
C
OSC
1
2
3
4
8
7
6
5
LTC1062
CLK IN = f
C
• 100
1062 TA05
C
0.01µF
C
0.01µF
12R
309.6k
V
IN
R
25.8k
V
–
= –5V
V
+
= 5V
DC OUTPUT
EXAMPLE:
f
CLK
= 100KHz, f
C
= 1kHz. THE FILTER ACCURATELY PASSES
THE HIGH DC INPUT AND ACTS AS 5TH ORDER LP FILTER
FOR THE AC SIGNALS RIDING ON THE DC
HIGH DC INPUT = 100V
f
IN
/f
C
0.01
–1.4
PASSBAND GAIN (dB)
–1.0
–0.6
0.2
0.1 1
1062 TA06
–0.2
–1.2
–0.8
0
–0.4
V
S
= ±5V
f
CLK
= 100kHz
Passband Amplitude Response for the
High DC Accurate 5th Order Filter
TYPICAL APPLICATIO S
U
9
LTC1062
1062fd
Cascading Two LTC1062s to Form a Very
Selective Clock Sweepable Bandpass Filter
FB
AGND
V
–
DIVIDER
RATIO
B
OUT
OUT
V
+
C
OSC
1
2
3
4
8
7
6
5
LTC1062
1062 TA07
V
IN
R1
10k
f
CLK
V
OUT
5V
–5V 5V
FB
AGND
V
–
DIVIDER
RATIO
B
OUT
OUT
V
+
C
OSC
1
2
3
4
8
7
6
5
LTC1062
–5V
R2
10k
R′1
10k
R′2
12.5k
FB
AGND
V
–
DIVIDER
RATIO
B
OUT
OUT
V
+
C
OSC
1
2
3
4
8
7
6
5
LTC1062
1062 TA08
V
IN
R1
–5V
f
CLK
V
OUT
5V
R2 R3
Clock Tunable Notch Filter
For Simplicity Use R3 = R4 = R5 = 10k;
–
+
R5R4
R5
R2
= 1.234, =
79.3
1
f
CLK
f
NOTCH
Frequency Response of the Bandpass Filter
(kHz)
0.5
(dB)
–80
–60
–40
–20
1
1.5 2 2.5
1062 TA09
3 3.5 4 4.5
0
–90
–70
–50
–30
10
20
–10
V
S
= ±5V
V
IN
= 100mV
RMS
= 1
R1
R2
= 0.8
R′1
R′2
Frequency Response of the Notch Filter
(Hz)
100
(dB)
–10
0
10
20
30
40
50
60
70
900
1062 TA10
300 500 700 1100
TYPICAL APPLICATIO S
U
P1-P3P4-P6P7-P9P10-P12P13-P15P16-P16

LTC1062CN8#PBF

Mfr. #:
Buy LTC1062CN8#PBF
Manufacturer:
Analog Devices Inc.
Description:
Active Filter Fifth Order Lowpass Filter
Lifecycle:
New from this manufacturer.
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