LM2576
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10
Procedure (Fixed Output Voltage Version) In order to simplify the switching regulator design, a step−by−step
design procedure and some examples are provided.
Procedure Example
Given Parameters:
V
out
= Regulated Output Voltage (3.3 V, 5.0 V, 12 V or 15 V)
V
in(max)
= Maximum Input Voltage
I
Load(max)
= Maximum Load Current
Given Parameters:
V
out
= 5.0 V
V
in(max)
= 15 V
I
Load(max)
= 3.0 A
1. Controller IC Selection
According to the required input voltage, output voltage and
current, select the appropriate type of the controller IC output
voltage version.
1. Controller IC Selection
According to the required input voltage, output voltage,
current polarity and current value, use the LM2576−5
controller IC
2. Input Capacitor Selection (C
in
)
To prevent large voltage transients from appearing at the input
and for stable operation of the converter, an aluminium or
tantalum electrolytic bypass capacitor is needed between the
input pin +V
in
and ground pin GND. This capacitor should be
located close to the IC using short leads. This capacitor should
have a low ESR (Equivalent Series Resistance) value.
2. Input Capacitor Selection (C
in
)
A 100 mF, 25 V aluminium electrolytic capacitor located near
to the input and ground pins provides sufficient bypassing.
3. Catch Diode Selection (D1)
A. Since the diode maximum peak current exceeds the
regulator maximum load current the catch diode current
rating must be at least 1.2 times greater than the maximum
load current. For a robust design the diode should have a
current rating equal to the maximum current limit of the
LM2576 to be able to withstand a continuous output short
B. The reverse voltage rating of the diode should be at least
1.25 times the maximum input voltage.
3. Catch Diode Selection (D1)
A. For this example the current rating of the diode is 3.0 A.
B. Use a 20 V 1N5820 Schottky diode, or any of the
suggested fast recovery diodes shown in Table 1.
4. Inductor Selection (L1)
A. According to the required working conditions, select the
correct inductor value using the selection guide from
Figures 18 to 22.
B. From the appropriate inductor selection guide, identify the
inductance region intersected by the Maximum Input
Voltage line and the Maximum Load Current line. Each
region is identified by an inductance value and an inductor
code.
C. Select an appropriate inductor from the several different
manufacturers part numbers listed in Table 2.
The designer must realize that the inductor current rating
must be higher than the maximum peak current flowing
through the inductor. This maximum peak current can be
calculated as follows:
where t
on
is the “on” time of the power switch and
For additional information about the inductor, see the
inductor section in the “Application Hints” section of
this data sheet.
I
p(max)
+ I
Load(max)
)
ǒ
V
in
–V
out
Ǔ
t
on
2L
t
on
+
V
out
V
in
x
1.0
f
osc
4. Inductor Selection (L1)
A. Use the inductor selection guide shown in Figures 19.
B. From the selection guide, the inductance area intersected
by the 15 V line and 3.0 A line is L100.
C. Inductor value required is 100 mH. From Table 2, choose
an inductor from any of the listed manufacturers.
LM2576
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11
Procedure (Fixed Output Voltage Version) (continued)In order to simplify the switching regulator design, a step−by−step
design procedure and some examples are provided.
Procedure Example
5. Output Capacitor Selection (C
out
)
A. Since the LM2576 is a forward−mode switching regulator
with voltage mode control, its open loop 2−pole−1−zero
frequency characteristic has the dominant pole−pair
determined by the output capacitor and inductor values. For
stable operation and an acceptable ripple voltage,
(approximately 1% of the output voltage) a value between
680 mF and 2000 mF is recommended.
B. Due to the fact that the higher voltage electrolytic capacitors
generally have lower ESR (Equivalent Series Resistance)
numbers, the output capacitor’s voltage rating should be at
least 1.5 times greater than the output voltage. For a 5.0 V
regulator, a rating at least 8.0 V is appropriate, and a 10 V or
16 V rating is recommended.
5. Output Capacitor Selection (C
out
)
A. C
out
= 680 mF to 2000 mF standard aluminium electrolytic.
B. Capacitor voltage rating = 20 V.
Procedure (Adjustable Output Version: LM2576−ADJ)
Procedure Example
Given Parameters:
V
out
= Regulated Output Voltage
V
in(max)
= Maximum DC Input Voltage
I
Load(max)
= Maximum Load Current
Given Parameters:
V
out
= 8.0 V
V
in(max)
= 25 V
I
Load(max)
= 2.5 A
1. Programming Output Voltage
To select the right programming resistor R1 and R2 value (see
Figure 2) use the following formula:
Resistor R1 can be between 1.0 k and 5.0 kW. (For best
temperature coefficient and stability with time, use 1% metal
film resistors).
V
out
+ V
ref
ǒ
1.0 )
R2
R1
Ǔ
R2 + R1
ǒ
V
out
V
ref
–1.0
Ǔ
where V
ref
= 1.23 V
1. Programming Output Voltage (selecting R1 and R2)
Select R1 and R2:
R2 = 9.91 kW, choose a 9.88 k metal film resistor.
R2 + R1
ǒ
V
out
V
ref
* 1.0
Ǔ
+ 1.8 k
ǒ
8.0 V
1.23 V
* 1.0
Ǔ
V
out
+ 1.23
ǒ
1.0 )
R2
R1
Ǔ
Select R1 = 1.8 kW
2. Input Capacitor Selection (C
in
)
To prevent large voltage transients from appearing at the input
and for stable operation of the converter, an aluminium or
tantalum electrolytic bypass capacitor is needed between the
input pin +V
in
and ground pin GND This capacitor should be
located close to the IC using short leads. This capacitor should
have a low ESR (Equivalent Series Resistance) value.
For additional information see input capacitor section in the
“Application Hints” section of this data sheet.
2. Input Capacitor Selection (C
in
)
A 100 mF, 150 V aluminium electrolytic capacitor located near
the input and ground pin provides sufficient bypassing.
3. Catch Diode Selection (D1)
A. Since the diode maximum peak current exceeds the
regulator maximum load current the catch diode current
rating must be at least 1.2 times greater than the maximum
load current. For a robust design, the diode should have a
current rating equal to the maximum current limit of the
LM2576 to be able to withstand a continuous output short.
B. The reverse voltage rating of the diode should be at least
1.25 times the maximum input voltage.
3. Catch Diode Selection (D1)
A. For this example, a 3.0 A current rating is adequate.
B. Use a 30 V 1N5821 Schottky diode or any suggested fast
recovery diode in the Table 1.
LM2576
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12
Procedure (Adjustable Output Version: LM2576−ADJ) (continued)
Procedure Example
4. Inductor Selection (L1)
A. Use the following formula to calculate the inductor Volt x
microsecond [V x ms] constant:
B. Match the calculated E x T value with the corresponding
number on the vertical axis of the Inductor Value Selection
Guide shown in Figure 22. This E x T constant is a
measure of the energy handling capability of an inductor and
is dependent upon the type of core, the core area, the
number of turns, and the duty cycle.
C. Next step is to identify the inductance region intersected by
the E x T value and the maximum load current value on the
horizontal axis shown in Figure 25.
D. From the inductor code, identify the inductor value. Then
select an appropriate inductor from Table 2.
The inductor chosen must be rated for a switching
frequency of 52 kHz and for a current rating of 1.15 x I
Load
.
The inductor current rating can also be determined by
calculating the inductor peak current:
where t
on
is the “on” time of the power switch and
For additional information about the inductor, see the
inductor section in the “External Components” section of
this data sheet.
ExT+
ǒ
V
in
–V
out
Ǔ
V
out
V
in
x
10
6
F[Hz]
[V x ms]
I
p(max)
+ I
Load(max)
)
ǒ
V
in
–V
out
Ǔ
t
on
2L
t
on
+
V
out
V
in
x
1.0
f
osc
4. Inductor Selection (L1)
A. Calculate E x T [V x ms] constant:
B. E x T = 80 [V x ms]
C. I
Load(max)
= 2.5 A
Inductance Region = H150
D. Proper inductor value = 150 mH
Choose the inductor from Table 2.
ExT+
(
25–8.0
)
x
8.0
25
x
1000
52
+ 80 [V x ms]
5. Output Capacitor Selection (C
out
)
A. Since the LM2576 is a forward−mode switching regulator
with voltage mode control, its open loop 2−pole−1−zero
frequency characteristic has the dominant pole−pair
determined by the output capacitor and inductor values.
For stable operation, the capacitor must satisfy the
following requirement:
B. Capacitor values between 10 mF and 2000 mF will satisfy
the loop requirements for stable operation. To achieve an
acceptable output ripple voltage and transient response, the
output capacitor may need to be several times larger than
the above formula yields.
C. Due to the fact that the higher voltage electrolytic capacitors
generally have lower ESR (Equivalent Series Resistance)
numbers, the output capacitor’s voltage rating should be at
least 1.5 times greater than the output voltage. For a 5.0 V
regulator, a rating of at least 8.0 V is appropriate, and a 10 V
or 16 V rating is recommended.
C
out
w 13,300
V
in(max)
V
out
xL[μH]
[μF]
5. Output Capacitor Selection (C
out
)
A.
To achieve an acceptable ripple voltage, select
C
out
= 680 mF electrolytic capacitor.
C
out
w 13,300 x
25
8 x 150
+ 332.5 μF

LM2576T-005

Mfr. #:
Manufacturer:
ON Semiconductor
Description:
Switching Voltage Regulators 5V 3A Buck PWM
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