10
LT1956/LT1956-5
1956f
APPLICATIO S I FOR ATIO
WUUU
Peak-to-peak output ripple voltage is the sum of a triwave
(created by peak-to-peak ripple current (I
LP-P
) times ESR)
and a square wave (created by parasitic inductance (ESL)
and ripple current slew rate). Capacitive reactance is
assumed to be small compared to ESR or ESL.
V I ESR ESL
dI
dt
RIPPLE LP P
=
()()
+
()
-
Σ
where:
ESR = equivalent series resistance of the output
capacitor
ESL = equivalent series inductance of the output
capacitor
dI/dt = slew rate of inductor ripple current = V
IN
/L
Peak-to-peak ripple current (I
LP-P
) through the inductor
and into the output capacitor is typically chosen to be
between 20% and 40% of the maximum load current. It is
approximated by:
I
VVV
VfL
LP P
OUT IN OUT
IN
-
=
()( )
()()()
Example: with V
IN
= 12V, V
OUT
= 5V, L = 15µH, ESR =
0.080 and ESL = 10nH, output ripple voltage can be
approximated as follows:
IA
dI
dt
V
mV
RIPPLE
LP-P
P-P
=
()
()
()
()( )
=
==
=
()()
+
()()
()
=+=
512 5
12 15 10 500 10
0 389
12
15 10
10 0 8
0 389 0 08 10 10 10 0 8
0 031 0 008 39
66
6
6
96
••
.
•.
.. .
..
––
Σ
To reduce output ripple voltage further requires an in-
crease in the inductor value with the trade-off being a
physically larger inductor with the possibility of increased
component height and cost.
Ceramic Output Capacitor
An alternative way to further reduce output ripple voltage
is to reduce the ESR of the output capacitor by using a
ceramic capacitor. Although this reduction of ESR re-
moves a useful zero in the overall loop response, this zero
can be replaced by inserting a resistor (R
C
) in series with
the V
C
pin and the compensation capacitor C
C
. (See
Ceramic Capacitors in Applications Information.)
Peak Inductor Current and Fault Current
To ensure that the inductor will not saturate, the peak in-
ductor current should be calculated knowing the maximum
load current. An appropriate inductor should then be cho-
sen. In addition, a decision should be made whether or not
the inductor must withstand continuous fault conditions.
If maximum load current is 0.5A, for instance, a 0.5A
inductor may not survive a continuous 2A overload condi-
tion. Dead shorts will actually be more gentle on the
inductor because the LT1956 has frequency and current
limit foldback.
Peak inductor and switch current can be significantly
higher than output current, especially with smaller induc-
tors and lighter loads, so don’t omit this step. Powdered
Table 2
VENDOR/ VALUE I
DC(MAX)
DCR HEIGHT
PART NO. (
µ
H) (Amps) (Ohms) (mm)
Coiltronics
UP1B-100 10 1.9 0.111 5.0
UP1B-220 22 1.2 0.254 5.0
UP2B-220 22 2.0 0.062 6.0
UP2B-330 33 1.7 0.092 6.0
UP1B-150 15 1.5 0.175 5.0
Coilcraft
D01813P-153HC 15 1.5 0.170 5.0
D01813P-103HC 10 1.9 0.111 5.0
D53316P-223 22 1.6 0.207 5.1
D53316P-333 33 1.4 0.334 5.1
LP025060B-682 6.8 1.3 0.165 1.65
Sumida
CDRH4D28-4R7 4.7 1.32 0.072 3.0
CDRH5D28-100 10 1.30 0.065 3.0
CDRH6D28-150 15 1.40 0.084 3.0
CDRH6D28-180 18 1.32 0.095 3.0
CDRH6D28-220 22 1.20 0.128 3.0
CDRH6D38-220 22 1.30 0.096 4.0
11
LT1956/LT1956-5
1956f
APPLICATIO S I FOR ATIO
WUUU
iron cores are forgiving because they saturate softly,
whereas ferrite cores saturate abruptly. Other core mate-
rials fall somewhere in between. The following formula
assumes continuous mode of operation, but errs only
slightly on the high side for discontinuous mode, so it can
be used for all conditions.
II
I
I
VVV
VfL
PEAK OUT
LP P
OUT
OUT IN OUT
IN
=+ =+
()
-
22
••
EMI
Decide if the design can tolerate an “open” core geometry
like a rod or barrel, which have high magnetic field
radiation, or whether it needs a closed core like a toroid to
prevent EMI problems. This is a tough decision because
the rods or barrels are temptingly cheap and small and
there are no helpful guidelines to calculate when the
magnetic field radiation will be a problem.
Additional Considerations
After making an initial choice, consider additional factors
such as core losses and second sourcing, etc. Use the
experts in Linear Technology’s Applications department if
you feel uncertain about the final choice. They have
experience with a wide range of inductor types and can tell
you about the latest developments in low profile, surface
mounting, etc.
MAXIMUM OUTPUT LOAD CURRENT
Maximum load current for a buck converter is limited by
the maximum switch current rating (I
P
). The current rating
for the LT1956 is 1.5A. Unlike most current mode convert-
ers, the LT1956 maximum switch current limit does not
fall off at high duty cycles. Most current mode converters
suffer a drop off of peak switch current for duty cycles
above 50%. This is due to the effects of slope compensa-
tion required to prevent subharmonic oscillations in cur-
rent mode converters. (For detailed analysis, see Applica-
tion Note 19.)
The LT1956 is able to maintain peak switch current limit
over the full duty cycle range by using patented circuitry to
cancel the effects of slope compensation on peak switch
current without affecting the frequency compensation it
provides.
Maximum load current would be equal to maximum
switch current for an infinitely large inductor, but with
finite inductor size, maximum load current is reduced by
one half of peak-to-peak inductor current (I
LP-P
). The
following formula assumes continuous mode operation,
implying that the term on the right is less than one half
of␣ I
P
.
I Continuous Mode
I
I
I
VVVVV
VfL
OUT MAX
P
LP P
P
OUT F IN OUT F
IN
()
––
––
==
+
()( )
()( )()()
-
22
For V
OUT
= 5V, V
IN(MAX)
= 8V, V
F(DI)
= 0.63V, f = 500kHz
and L = 10µH:
I
A
OUT MAX()
.–
.–.
••
.–. .
=
+
()( )
()()
()()
==
15
5 0 63 8 5 0 63
2 8 500 10 10 10
15 017 133
36
Note that there is less load current available at the higher
input voltage because inductor ripple current increases. At
V
IN
= 15V and using the same set of conditions:
I
A
OUT MAX()
.–
.–.
••
.–. .
=
+
()( )
()( )
()()
==
15
5 0 63 15 5 0 63
2 15 500 10 10 10
15 035 115
36
To calculate peak switch current with a given set of
conditions, use:
II
I
I
VVVVV
VfL
SW PEAK OUT
LP P
OUT
OUT F IN OUT F
IN
()
––
=+
=+
+
()( )
()( )()()
-
2
2
Reduced Inductor Value and Discontinuous Mode
If the smallest inductor value is of the most importance to
a converter design, in order to reduce inductor size/cost,
discontinuous mode may yield the smallest inductor
12
LT1956/LT1956-5
1956f
APPLICATIO S I FOR ATIO
WUUU
load current is required, the inductor value must be
increased. If I
OUT(MAX)
no longer meets the discontinuous
mode criteria, use the I
OUT(MAX)
equation for continuous
mode; the LT1956 is designed to operate well in both
modes of operation, allowing a large range of inductor
values to be used.
SHORT-CIRCUIT CONSIDERATIONS
For a ground short-circuit fault on the regulated output,
the maximum input voltage for the LT1956 is typically
limited to 25V. If a greater input voltage is required,
increasing the resistance in series with the inductor may
suffice (see short-circuit calculations at the end of this
section). Alternatively, the 1.5A LT1766 can be used since
it is identical to the LT1956 but runs at a lower frequency
of 200kHz, allowing higher sustained input voltage capa-
bility during output short circuit.
The LT1956 is a current mode controller. It uses the V
C
node voltage as an input to a current comparator which
turns off the output switch on a cycle-by-cycle basis as
peak switch current is reached. The internal clamp on the
V
C
node, nominally 2V, then acts as an output switch peak
current limit. This action becomes the switch current limit
specification. The maximum available output power is
then determined by the switch current limit.
A potential controllability problem could occur under
short-circuit conditions. If the power supply output is
short circuited, the feedback amplifier responds to the low
output voltage by raising the control voltage, V
C
, to its
peak current limit value. Ideally, the output switch would
be turned on, and then turned off as its current exceeded
the value indicated by V
C
. However, there is finite response
time involved in both the current comparator and turnoff
of the output switch. These result in a minimum on time
t
ON(MIN)
. When combined with the large ratio of V
IN
to
(V
F
+ I • R), the diode forward voltage plus inductor I • R
voltage drop, the potential exists for a loss of control.
Expressed mathematically the requirement to maintain
control is:
ft
VIR
V
ON
F
IN
+
solu
tion. The maximum output load current in discontinu-
ous mode, however, must be calculated and is defined
later in this section.
Discontinuous mode is entered when the output load
current is less than one-half of the inductor ripple current
(I
LP-P
). In this mode, inductor current falls to zero before
the next switch turn-on (see Figure 8). Buck converters
will be in discontinuous mode for output load current
given by:
I Discontinous Mode
VVVVV
VfL
OUT
OUT F IN OUT F
IN
<
+()()
()( )()()2
The inductor value in a buck converter is usually chosen
large enough to keep inductor ripple current (I
LP-P
) low;
this is done to minimize output ripple voltage and maxi-
mize output load current. In the case of large inductor
values, as seen in the equation above, discontinuous
mode will be associated with “light loads.”
When choosing small inductor values, however, discon-
tinuous mode will occur at much higher output load
currents. The limit to the smallest inductor value that can
be chosen is set by the LT1956 peak switch current (I
P
)
and the maximum output load current required given by:
I
OUT(MAX)
LP-P
DiscontinuousMode
I
I
IfLV
VVVVV
PPIN
OUT F IN OUT F
==
+−
22
22()
()()( )
()( )
Example: For V
IN
= 15V, V
OUT
= 5V, V
F
= 0.63V, f = 500kHz
and L = 4µH
I Discontinuous Mode
OUT MAX()
. ( )( )( )
(.)(.)
=
+
1 5 500 10 4 10 15
25063155063
236
I
OUT(MAX)
Discontinuous Mode = 0.639A
What has been shown here is that if high inductor ripple
current and discontinuous mode operation can be toler-
ated, small inductor values can be used. If a higher output

LT1956IFE#PBF

Mfr. #:
Manufacturer:
Analog Devices / Linear Technology
Description:
Switching Voltage Regulators Hi V, 1.5A, 500kHz Buck Sw Regs
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