LTC3643
16
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APPLICATIONS INFORMATION
Figure 7 shows a simplified block diagram for the applica-
tion in Figure 6, and can be used to analyze the stability
of the application with the given compensation compo-
nents.
Figure 6. 5V to 40V Boost Application
Figure 7. Block Diagram of the Boost Regulator
POWER SUPPLY (5V)
CLP V
IN
INDIS
LTC3643
SW BOOST
SYSTEM LOAD
3643 F06
CAP
40V
FBCAP
GATE
ITH
SGND PGND
L1
4.7µH
C2
0.1µF
47µF
RFB1
392k
C
OUT
47µF
R
OUT
RFB2
6.04k
R
ITH
402k
C
ITH2
2.2pF
C
ITH1
470pF
0.6V
V
ITH
I
OUT
V
OUT
ERROR
AMPLIFIER
OUTPUT
IMPEDANCE
3643 F07
POWER STAGE
TRANSCONDUCTANCE
AMPLIFIER
FEEDBACK
GAIN
+
A
EA
G
MP
Z
OUT
A
FB
G
MP
is the transconductance gain from V
ITH
to I
OUT
.
Because of the architecture of the regulator, the gain from
V
ITH
to I
L
(inductor current) is fixed internally to be 3mmho.
Furthermore, the DC gain from I
L
to I
OUT
is equal to A
MP
:
A
MP
=
η V
IN
V
CAP
A / A
Where η is the efficiency of the regulator. Assuming a 90%
efficiency and a 5V in to 40V out application:
A
MP
= 0.1125 A/A
The AC component of the G
mp
can be mainly attributed
to the RHP zero of the boost regulator, Z
2
:
Z
2
=
V
IN
2
2π P
OUT(MAX)
L
1
Hz
Since P
OUT(MAX)
= V
IN
• I
L(MAX)
η,
Z
2
=
V
IN
2π ηI
L(MAX)
L
1
= 94kHz
The total loop must be compensated such that the crossover
frequency is at least 10× slower than that of Z
2
.
Z
OUT
is the output impedance of the application. It has a
DC gain of R
OUT
and a pole at P
1
:
P
1
=
1
2π R
OUT
C
OUT
Hz
A
EA
signifies the voltage gain of the internal error ampli-
fier. It translates a difference of FB input error to the
output I
TH
voltage. The g
m
of the error amplifier, g
m
(EA),
is fixed to the regulator and is typically 210µmho. With the
compensation network on ITH, for frequencies above the
error amplifier zero, Z1, the gain is roughly A
EA(FLATBAND)
.
Z
1
=
1
2π R
ITH
C
ITH1
= 0.85kHz
A
EA(FLATBAND)
= g
m
(EA)R
ITH1
= 82.8V / V
C
ITH2
is used purely to filter out high frequency signals
and as long as it is sized significantly smaller than C
ITH1
,
it should not affect the loop stability of the regulator.
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APPLICATIONS INFORMATION
As a result, the load pole has a unity gain impedance at:
1
2π C
OUT
= 6.8kHz
The last component of the loop is A
FB
, which is the gain
from V
OUT
to V
FB
, and in this application, it is simply
0.015 V/V.
For a rough estimation of the crossover frequency of the
entire loop, analysis can be done at frequency Z
1
. At that
frequency:
A
EA
A
EA(FLATBAND)
= 82.8V / V
G
MP
3 A
MP
= 0.33Ω
Z
OUT
P
Z
Z
1
= 8Ω
A
FB
= 0.015V / V
The total loop gain at Z1 is thus equal to the product of
all the components which is 3.27V/V. In addition, at that
frequency, since the zero frequency of the error amplifier
has already been reached, the system looks like a single
pole system, thus making the crossover frequency roughly:
3.27 • Z1 = 2.8kHz.
For applications where a large energy reservoir capacitor
is placed in parallel to the C
OUT
, the Z
OUT
component of
the block diagram needs to be remodeled, but often times,
the zero frequency of the ESR of the large capacitor and
its capacitance is well below the crossover frequency of
the loop, and can be ignored in analyzing the stability of
the loop.
Buck Mode
Transient Response
The buck mode transient response can be checked by
looking at the load response. Switching regulators take
several cycles to respond to a step in load current. When
a load step occurs, V
IN
immediately shifts by an amount
equal to the
ΔI
LOAD
ESR, where ESR is the effective
series resistance of C
IN
. ΔI
LOAD
also begins to charge or
discharge C
IN
generating a feedback error signal used
by the regulator to return V
IN
to its steady-state value.
During this recovery time, V
IN
can be monitored for over-
shoot or ringing that would indicate a stability problem.
The compensation for the buck mode of the LTC3643 is
implemented internal to the IC.
The initial output voltage step may
not be within the
bandwidth of the feedback loop, so the standard second
order overshoot/DC ratio cannot be used to determine
phase margin.
The output voltage settling behavior is related to the stability
of the closed-loop system and will demonstrate the actual
overall supply performance. For a detailed explanation of
optimizing the compensation components, including a
review of control loop theory, refer to Application Note
76.
In some applications, a more severe transient can be caused
by switching in loads with large (>1µF) input capacitors.
The discharged input capacitors are effectively put in
parallel with C
IN
, causing a rapid drop in V
IN
. No regula-
tor can deliver enough current to prevent this problem if
the switch connecting the load has low resistance and is
driven quickly. The solution is to limit the
turn-on speed of
the load switch driver. A Hot Swap controller is designed
specifically for this purpose and usually incorporates
current limiting, short-circuit protection and soft-starting.
Efficiency Considerations
The percent efficiency of a switching regulator is equal to
the output power divided by the input power times 100%.
It is often useful to analyze individual losses to determine
what is limiting the efficiency and which
change would
produce the most improvement. Percent efficiency can
be expressed as:
% Efficiency = 100% – (L1 + L2 + L3 +…)
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APPLICATIONS INFORMATION
where L1, L2, etc. are the individual losses as a percentage
of input power. Although all dissipative elements in the
circuit produce losses, three main sources usually account
for most of the losses in LTC3643 circuits: 1) I
2
R losses,
2) switching and biasing losses, and 3) other losses.
1. I
2
R losses are calculated from the DC resistances of
the internal switches, R
SW
, and external inductor, R
L
.
In continuous mode, the average input current flows
through inductor L and front end disconnect switch
but ischopped” between the internal top and bottom
power MOSFETs. Thus, the series resistance looking
into the SW pin is a function of both top and bottom
MOSFET R
DS(ON)
and the duty cycle (DC) as follows:
R
SW
= (R
DS(ON)TOP
)(1-DC) + (R
DS(ON)BOT
) (DC) +
R
DS(ON)BLKFET
The R
DS(ON)
for both the top and bottom MOSFETs can be
obtained from the Typical Performance Characteristics
curves. Thus to obtain I
2
R losses:
I
2
R losses = I
L
2
(R
SW
+ R
L
)
2. The switching current is the sum of the MOSFET driver
and control currents. The power MOSFET driver current
results from switching the gate capacitance of the power
MOSFETs. Each time a power MOSFET gate is switched
from low to high to low again, a packet of charge dQ
moves from V
IN
to ground. The resulting dQ/dt is a
current out of V
IN
that is typically much larger than the
DC control bias current. In continuous mode, I
GATECHG
= f(Q
T
+ Q
B
), where Q
T
and Q
B
are the gate charges of
the internal top and bottom power MOSFETs and f is
the switching frequency. The power loss is thus:
Switching Loss = I
GATECHG
• V
IN
3. Otherhidden” losses such as transition loss and cop-
per trace and internal load resistances can account for
additional efficiency degradations in the overall power
system. It is very important to include thesesystem”
level losses in the design of a system. Transition loss
arises from the brief amount of time the top power
MOSFET spends in the saturated region during switch
node transitions. The LTC3643 internal
power devices
switch quickly enough that these losses are not signifi-
cant compared to other sources. Other losses including
diode conduction losses during dead-time and inductor
core losses which generally account for less than 2%
total additional loss.
Thermal Conditions
In a majority of applications, the LTC3643 does not dis-
sipate much heat due to its high efficiency and low thermal
resistance of its exposed-back QFN
package. However, in
applications where the LTC3643 is running at high ambient
temperature, high V
IN
, and maximum output load current,
the heat dissipated may exceed the maximum junction
temperature of the part. If the junction temperature reaches
approximately 160°C, both power switches will be turned
off until the temperature drops about 15°C cooler.
To avoid the LTC3643 from exceeding the maximum
junction temperature, some thermal
analysis must be done.
The goal of the thermal analysis is to determine whether
the power dissipated exceeds the maximum junction
temperature of the part. The temperature rise is given by:
t
RISE
= P
D
θ
JA
As an example, consider the case when the LTC3643 is
used in applications where V
IN
= 5V, I
L
= 2A, and V
CAP
=
40V. The equivalent power MOSFET resistance R
SW
is:
R
SW
= R
DS(ON)TOP
V
IN
V
CAP
+R
DS(ON)BOT
1–
V
IN
V
CAP
+ R
DS(ON)BLKFET
= 150mΩ
5V
40V
+ 75mΩ 1–
5V
40V
+ 50mΩ
= 134mΩ
Typically, the current drawn from INTV
CC
will be 10mA.
Therefore, the total power dissipated by the part is:
P
D
= I
OUT
2
R
SW
+ V
IN
I
INTVCC
= 4A
2
134mΩ + 5V 10mA
= 587.5mW

LTC3643IUDD#TRPBF

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Power Management Specialized - PMIC 2A Bidirectional Charger/ Regulator for System Power Backup
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